NOx

There are three sources of NOx emissions; thermal, prompt, and fuel. The transport equation that is used to solve for NOx is the same for all NOx models, with the addition of reacting source terms to account for each NOx source.

NOx concentration is usually low compared to other species in combustion systems. As a result, it is generally agreed that NOx chemistry has negligible influence and can be decoupled from the main combustion and flow field calculations.

Figure 1. EQUATION_DISPLAY
ρ Y N O X t + ∇⋅ [ ρ v Y N O X [ ρ D f + μ t σ t ] Y N O X ] = ω ˙ N O X , t h e r m + ω ˙ N O X , p r o m p t + ω ˙ N O X , f u e l
(3608)

NOx Thermal

The NOx Thermal model solves the transport equation for NO with the thermal source term ω ˙ N O X , t h e r m

Formation of nitric oxide during combustion of hydrocarbons is temperature-dependent for the NOx Thermal model. It is produced by the reaction of atmospheric nitrogen with oxygen at elevated temperatures.

Thermal NOx is formed by high temperature oxidation of atmospheric nitrogen. For thermal nitric oxide, the principal reactions are generally recognized to be those proposed by the following three extended Zeldovich mechanisms:

Figure 2. EQUATION_DISPLAY
k 1 N 2 + O N O + N k - 1
(3609)
Figure 3. EQUATION_DISPLAY
k 2 N + O 2 N O + O k - 2
(3610)
Figure 4. EQUATION_DISPLAY
k 3 N + O H N O + H k - 3
(3611)

The rate constants for these reactions have been measured in numerous experimental studies, and the data obtained from these studies has been critically evaluated by Baulch et al. [775]. The expressions for rate coefficients of reactions are given below (in units of m 3 ( kmol ) - 1 s - 1 ):

Figure 5. EQUATION_DISPLAY
k 1 = 1.8 × 10 11 e ( 38370 T )
(3612)
Figure 6. EQUATION_DISPLAY
k - 1 = 3.8 × 10 10 e ( 425 T )
(3613)
Figure 7. EQUATION_DISPLAY
k 2 = 1.8 × 10 7 T e ( 4680 T )
(3614)
Figure 8. EQUATION_DISPLAY
k - 2 = 3.8 × 10 6 T e ( 20820 T )
(3615)
Figure 9. EQUATION_DISPLAY
k 3 = 7.1 × 10 10 e ( 450 T )
(3616)
Figure 10. EQUATION_DISPLAY
k - 3 = 1.7 × 10 11 e ( 24560 T )
(3617)

where k 1 , k 2 and k 3 are the forward rate constants and k - 1 , k - 2 and k - 3 are the backward rate constants for NOx reactions, respectively. The rate of formation of NOx is significant only at high temperatures since the thermal fixation of nitrogen requires the breaking of a strong N2 bond. This effect is represented by the high activation energy of the first reaction of the mechanism, which makes this reaction the rate-limiting step of the Zeldovich mechanism.

For the Complex Chemistry or Eddy Break-Up combustion models, if the concentrations of radicals O, OH and H are calculated by the combustion model, they are used in the NOx model. Otherwise, certain assumptions have to be made to obtain their values. The concentration of radical H is assumed to be zero. Two approaches are being used to solve the O-concentration:
Figure 11. EQUATION_DISPLAY
[ O ] = k p [ O 2 ] 1 / 2
(3618)
  • Equilibrium Approach

    where:

    Figure 12. EQUATION_DISPLAY
    k p = 1.255 × 10 4 T - 1 / 2 e ( 31090 T )
    (3619)
  • Partial Equilibrium Approach

    This approach considers a third-body reaction, which leads to a different expression for k p :

    Figure 13. EQUATION_DISPLAY
    k p = 1.16 × T 1 / 2 e ( 27123 T )
    (3620)

    The partial equilibrium approach generally predicts higher O-concentrations than the equilibrium approach.

There are also two approaches being used to solve the OH-concentration:
  • Exclusion Approach

    In this approach, the third reaction in the extended Zeldovich mechanism is assumed to be negligible through the following observation:

    Figure 14. EQUATION_DISPLAY
    k 2 [ O 2 ] eq  >>  k 3 [ O H ] eq
    (3621)
  • Partial Equilibrium Approach

    With this approach, the OH-concentration is given as:

    Figure 15. EQUATION_DISPLAY
    [ O H ] = 6.7331 * T - 0.57 e ( 4595 T ) [ O ] 1 / 2 [ H 2 O ] 1 / 2
    (3622)
The net rate of formation of NO is given by:
Figure 16. EQUATION_DISPLAY
d [ N O ] d t = k 1 [ O ] [ N 2 ] + k 2 [ N ] [ O 2 ] + k 3 [ N ] [ O H ] - k - 1 [ N O ] [ N ] - k - 2 [ N O ] [ O ] - k - 3 [ N O ] [ H ]
(3623)
where [ X ] is molar concentration of X (in units of   kmol   m - 3 s - 1 ). The activation energy for oxidation of N is small, hence a quasi-steady state can be established:
Figure 17. EQUATION_DISPLAY
d [ N ] d t = 0 = k 1 [ O ] [ N 2 ] - k 2 [ N ] [ O 2 ] - k 3 [ N ] [ O H ] - k - 1 [ N O ] [ N ] + k - 2 [ N O ] [ O ] + k - 3 [ N O ] [ H ] [ N ] = k 1 [ O ] [ N 2 ] + k - 2 [ N O ] [ O ] + k - 3 [ N O ] [ H ] k - 1 [ N O ] + k 2 [ O 2 ] + k 3 [ O H ]
(3624)
Based on this assumption, the instantaneous rate of formation of NOx is (in units of   kmol   m - 3 s - 1 ):
Figure 18. EQUATION_DISPLAY
d [ N O ] d t = k 1 [ O ] [ N 2 ] - k - 2 [ N O ] [ O ] - k - 3 [ N O ] [ H ] + k 1 [ O ] [ N 2 ] + k - 2 [ N O ] [ O ] + k - 3 [ N O ] [ H ] k - 1 [ N O ] + k 2 [ O 2 ] + k 3 [ O H ] ( k 2 [ O 2 ] + k 3 [ O H ] - k - 1 [ N O ] )
(3625)

which can be simplified further to the expression:

Figure 19. EQUATION_DISPLAY
ω˙NOX,therm=2AC2BD[NO]2C+D[NO]
(3626)
where:
Figure 20. EQUATION_DISPLAY
A = k 1 [ O ] [ N 2 ] B = k - 2 [ O ] + k - 3 [ H ] C = k 2 [ O 2 ] + k 3 [ O H ] D = k - 1
(3627)
When modeling NOx with flamelet models, the values for the coefficients A, B, C, and D are stored in the flamelet table. The flamelet model can then calculate the flamelets source term without calculating for each species.

If both the NOx Thermal and NOx Prompt models are activated, then the net production rate of NOx is the sum of the thermal and prompt NOx.

NOx Prompt

The formation of prompt NOx involves complex reactions with many intermediate species such as CH, CH2, HCN, CN, and others. These complex mechanisms are simplified to a global rate.

For most hydrocarbon fuels, the production rate of prompt NOx is taken from the global kinetics parameters derived by De Soete [776] and represented by the following equations:

Figure 21. EQUATION_DISPLAY
ω ˙ N O X , p r o m p t = k r M w N O X
(3628)

Where M w N O X is the molecular weight of NOx and k r is the rate constant given by:

Figure 22. EQUATION_DISPLAY
k r = c f ( F ) A [ O 2 ] a [ N 2 ] [ Fuel ] e ( E A R u T )
(3629)
E A is the activation energy. A is the pre-exponential factor that is given by:
Figure 23. EQUATION_DISPLAY
A = 6.4 × 10 6 ( R u T / p ) ( a + 1 )
(3630)
c f is the correction factor that is used to change the value of the pre-exponential factor, for a particular hydrocarbon whose kinetics data is known to you.
The factor F is computed internally for a given fuel as follows [777]:
Figure 24. EQUATION_DISPLAY
F = 4.75 + 0.081 ( n ) 23.2 Φ + 32 Φ 2 12.2 Φ 3
(3631)
where n is the number of carbon atoms in the hydrocarbon fuel, and Φ is the equivalence ratio.
The value of a varies with the oxygen mole fraction X O 2 as follows:
X O 2 4.1 × 10 - 3 a = 1
4.1 × 10 - 3 < X O 2 1.11 × 10 - 2 a = - 3.95 - 0.9 ln X O 2
1.11 × 10 - 2 < X O 2 < 0.03 a = 0.35 - 0.1 ln X O 2
X O 2 0.03 a = 0

If both the NOx Thermal and NOx Prompt models are activated, then the net production rate of NOx is the sum of the thermal and prompt NOx.

NOx Fuel

The NOx Fuel model solves three transport equations for NO, HCN, and NH3. Each of these transport equation includes the source terms ω ˙ N O , ω ˙ H C N , and ω ˙ N H 3 . These source terms are calculated as:
Figure 25. EQUATION_DISPLAY
ω ˙ H C N = ω ˙ H C N , produced + ω ˙ H C N , consumed ω ˙ N H 3 = ω ˙ N H 3 , produced + ω ˙ N H 3 , consumed ω ˙ N O = ω ˙ N O , produced + ω ˙ N O , consumed
(3632)

When using the Lagrangian phase models—Liquid Fuel NOx or Coal Fuel NOx—these source terms are derived as shown below.

Liquid Fuel NOx
For liquid fuel, the only source of nitrogen is the evaporating fuel. The intermediates formed can be HCN or NH3. The fuel can also form NO through other pathways. There is also a possibility that N2 is formed as one of the intermediate species. The following figure shows the possible routes.


For multi-component droplets such as C x H y N z + H 2 O , you identify the fuel species. Only the fuel C x H y N z source is needed.
Figure 26. EQUATION_DISPLAY
ω ˙ H C N , produced = ( ω ˙ fuel ) ( Y N ) ( c f ) ( Z H C N ) ( M w H C N ) ( M w N ) ( V ) ω ˙ N H 3 , produced = ( ω ˙ fuel ) ( Y N ) ( c f ) ( Z N H 3 ) ( M w N H 3 ) ( M w N ) ( V )
(3633)
where ω ˙ fuel is the rate of evaporation of liquid fuel [kg/s], V is the cell volume, and c f is a correction factor for fuel NOx.
ω ˙ N O , produced consists of NO produced from the fuel directly and/or NO produced by the oxidation of HCN/NH3:
Figure 27. EQUATION_DISPLAY
ω ˙ N O , produced = ω ˙ N O , direct + ω ˙ N O , oxidation
(3634)
Figure 28. EQUATION_DISPLAY
ω ˙ N O , direct = ( ω ˙ fuel ) ( Y N ) ( c f ) ( Z N O ) ( M w N O ) ( M w N ) ( V )
(3635)
There are four types of reactions:
Figure 29. EQUATION_DISPLAY
H C N + O 2 ( R 1 H C N ) l e a d s t o N O p r o d u c t i o n H C N + N O ( R 2 H C N ) l e a d s t o N O c o n s u m p t i o n N H 3 + O 2 ( R 1 N H 3 ) l e a d s t o N O p r o d u c t i o n N H 3 + N O ( R 2 N H 3 ) l e a d s t o N O c o n s u m p t i o n
(3636)
The kinetics rates are obtained from De Soete [776].
For intermediate species HCN:
Figure 30. EQUATION_DISPLAY
R 1 - H C N = A 1 - H C N X H C N X O 2 a e - E 1 , H C N / ( R T ) R 2 - H C N = A 2 - H C N X H C N X N O a e - E 2 , H C N / ( R T )
(3637)
where: R 1 , R 2 = conversion rates of  H C N ( S - 1 ) X = mole fractions A 1 , H C N = 1.0 × 10 10 ( S - 1 ) A 2 , H C N = 3.0 × 10 12 ( S - 1 ) E 1 , H C N = 280451.95  J/gmol E 2 , H C N = 251151  J/gmol
X O 2 4.1 × 10 - 3 a = 1
4.1 × 10 - 3 < X O 2 1.11 × 10 - 2 a = - 3.95 - 0.9 ln X O 2
1.11 × 10 - 2 < X O 2 < 0.03 a = 0.35 - 0.1 ln X O 2
X O 2 0.03 a = 0
For intermediate species NH3:
Figure 31. EQUATION_DISPLAY
R 1 - N H 3 = A 1 , N H 3 X N H 3 X O 2 a e - E 1 , N H 3 / ( R T ) R 2 - N H 3 = A 2 , N H 3 X N H 3 X N O a e - E 2 , N H 3 / ( R T )
(3638)
R 1 , R 2 = conversion rates of  N H 3 ( S - 1 ) A 1 , N H 3 = 4.0 × 10 6 ( S - 1 ) A 2 , N H 3 = 1.8 × 10 8 ( S - 1 ) E 1 , N H 3 = 133947.2  J/gmol E 2 , N H 3 = 113017.95  J/gmol
From Eqn. (3632):
Figure 32. EQUATION_DISPLAY
ω ˙ H C N , consumed = ω ˙ H C N - 1 + ω ˙ H C N - 2                                                 = - ( R 1 , H C N + R 2 , H C N ) ρ M w H C N M ¯ w
(3639)
Figure 33. EQUATION_DISPLAY
ω ˙ N H 3 , consumed = ω ˙ N H 3 - 1 + ω ˙ N H 3 - 2                                                = - ( R 1 , N H 3 + R 2 , N H 3 ) ρ M w N H 3 M ¯ w
(3640)
From Eqns. Eqn. (3634) and Eqn. (3632):
Figure 34. EQUATION_DISPLAY
ω ˙ N O , oxidation = ( R 1 , H C N + R 1 , N H 3 ) ρ M w N O M ¯ w
(3641)
Figure 35. EQUATION_DISPLAY
ω ˙ N O , consumed = ( R 2 , H C N + R 2 , N H 3 ) ρ M w N O M ¯ w
(3642)
So putting together all equations:
Figure 36. EQUATION_DISPLAY
ω ˙ H C N = ( ω ˙ fuel ) ( Y N ) ( c f ) ( Z H C N ) ( M w H C N ) ( M w N ) ( V ) ( R 1 , H C N + R 2 , H C N ) ρ M w H C N M ¯ w
(3643)
Figure 37. EQUATION_DISPLAY
ω ˙ N H 3 = ( ω ˙ fuel ) ( Y N ) ( c f ) ( Z N H 3 ) ( M w N H 3 ) ( M w N ) ( V ) ( R 1 , N H 3 + R 2 , N H 3 ) ρ M w H C N M ¯ w
(3644)
Figure 38. EQUATION_DISPLAY
ω ˙ N O = ( ω ˙ fuel ) ( Y N ) ( c f ) ( Z N O ) ( M w N O ) ( M w N ) ( V )                        +    ( R 1 , H C N + R 1 , N H 3 - R 2 , H C N - R 2 , N H 3 ) ρ M w N O M ¯ w
(3645)
Coal NOx
Unlike the liquid fuel NOx, coal nitrogen is divided into volatile bound N and char bound N.

Figure 39. EQUATION_DISPLAY
ω ˙ H C N , produced =     ( ω ˙ devol ) ( Y N , vol ) ( c f ) ( Z H C N ) ( M w H C N ) ( M w N ) ( V )   +    ( ω ˙ char-oxi ) ( Y N , char ) ( c f ) ( Z H C N ) ( M w H C N ) ( M w N ) ( V )
(3646)
ω ˙ H C N , consumed = - ( R 1 , H C N + R 2 , H C N ) ρ M w H C N M ¯ w (as in Eqn. (3639))
Figure 40. EQUATION_DISPLAY
ω ˙ N H 3 , produced =     ( ω ˙ devol ) ( Y N , vol ) ( c f ) ( Z N H 3 ) ( M w H C N ) ( M w N ) ( V )   +    ( ω ˙ char-oxi ) ( Y N , char ) ( c f ) ( Z N H 3 ) ( M w H C N ) ( M w N ) ( V )
(3647)
ω ˙ N H 3 , consumed = - ( R 1 , N H 3 + R 2 , N H 3 ) ρ M w N H 3 M ¯ w (as in Eqn. (3640))
Note that the values for c f , Z H C N , Z N H 3 and Z N O can be specified differently for char and volatile.
Figure 41. EQUATION_DISPLAY
ω ˙ N O , direct =     ( ω ˙ devol ) ( Y N , vol ) ( c f ) ( Z N O ) ( M w N O ) ( M w N ) ( V )   +    ( ω ˙ char-oxi ) ( Y N , char ) ( c f ) ( Z N O ) ( M w N O ) ( M w N ) ( V )
(3648)
The values for ω ˙ N O , oxidation and ω ˙ N O , consumed are the same as in Eqn. (3641) and Eqn. (3642). There is some restriction in choosing values for the mass fraction of char Y N , char and the mass fraction of coal Y N , vol —they are not independent of each other. You need ultimate and proximate analysis. Ultimate analysis indicates the percentage of elemental N in coal, that is, the mass fraction of N Y N in dry ash free (daf) coal:
Figure 42. EQUATION_DISPLAY
Y N = Y N , vol + Y N , c h a r
(3649)
Proximate analysis provides the mass fractions of vol and char, along with other coal components. Always make sure that Eqn. (3649) is satisfied.